5/(2x^2+3x-6)=0

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Solution for 5/(2x^2+3x-6)=0 equation: 


D( x )

2*x^2+3*x-6 = 0

2*x^2+3*x-6 = 0

2*x^2+3*x-6 = 0

2*x^2+3*x-6 = 0

DELTA = 3^2-(-6*2*4)

DELTA = 57

DELTA > 0

x = (57^(1/2)-3)/(2*2) or x = (-57^(1/2)-3)/(2*2)

x = (57^(1/2)-3)/4 or x = (-(57^(1/2)+3))/4

x in (-oo:(-(57^(1/2)+3))/4) U ((-(57^(1/2)+3))/4:(57^(1/2)-3)/4) U ((57^(1/2)-3)/4:+oo)

5/(2*x^2+3*x-6) = 0

2*x^2+3*x-6 = 0

2*x^2+3*x-6 = 0

DELTA = 3^2-(-6*2*4)

DELTA = 57

DELTA > 0

x = (57^(1/2)-3)/(2*2) or x = (-57^(1/2)-3)/(2*2)

x = (57^(1/2)-3)/4 or x = (-(57^(1/2)+3))/4

(x+(57^(1/2)+3)/4)*(x-((57^(1/2)-3)/4)) = 0

5/((x+(57^(1/2)+3)/4)*(x-((57^(1/2)-3)/4))) = 0

x belongs to the empty set

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